Base | Representation |
---|---|
bin | 111110110010011… |
… | …101011010111111 |
3 | 2201102012000212012 |
4 | 332302131122333 |
5 | 4124133240403 |
6 | 252310201435 |
7 | 35050611026 |
oct | 7662353277 |
9 | 2642160765 |
10 | 1053415103 |
11 | 4a06973a4 |
12 | 25495327b |
13 | 13a31cb60 |
14 | 9dc938bd |
15 | 62732ed8 |
hex | 3ec9d6bf |
1053415103 has 4 divisors (see below), whose sum is σ = 1134447048. Its totient is φ = 972383160.
The previous prime is 1053415079. The next prime is 1053415127. The reversal of 1053415103 is 3015143501.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3015143501 = 409 ⋅7371989.
It is an interprime number because it is at equal distance from previous prime (1053415079) and next prime (1053415127).
It is a cyclic number.
It is not a de Polignac number, because 1053415103 - 28 = 1053414847 is a prime.
It is a super-2 number, since 2×10534151032 = 2219366758457001218, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1053415133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40515953 + ... + 40515978.
It is an arithmetic number, because the mean of its divisors is an integer number (283611762).
Almost surely, 21053415103 is an apocalyptic number.
1053415103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1053415103 is a deficient number, since it is larger than the sum of its proper divisors (81031945).
1053415103 is an equidigital number, since it uses as much as digits as its factorization.
1053415103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81031944.
The product of its (nonzero) digits is 900, while the sum is 23.
The square root of 1053415103 is about 32456.3568966081. The cubic root of 1053415103 is about 1017.4971002459.
Adding to 1053415103 its reverse (3015143501), we get a palindrome (4068558604).
The spelling of 1053415103 in words is "one billion, fifty-three million, four hundred fifteen thousand, one hundred three".
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