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10534147 = 13810319
BaseRepresentation
bin101000001011…
…110100000011
3201211012010121
4220023310003
510144043042
61013441111
7155352541
oct50136403
921735117
1010534147
115a45508
123640197
13224aa30
141582d91
15dd1367
hexa0bd03

10534147 has 4 divisors (see below), whose sum is σ = 11344480. Its totient is φ = 9723816.

The previous prime is 10534127. The next prime is 10534177. The reversal of 10534147 is 74143501.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74143501 = 211351391.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10534147 is a prime.

It is a super-2 number, since 2×105341472 = 221936506035218, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10534127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 405147 + ... + 405172.

It is an arithmetic number, because the mean of its divisors is an integer number (2836120).

Almost surely, 210534147 is an apocalyptic number.

10534147 is a deficient number, since it is larger than the sum of its proper divisors (810333).

10534147 is an equidigital number, since it uses as much as digits as its factorization.

10534147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 810332.

The product of its (nonzero) digits is 1680, while the sum is 25.

The square root of 10534147 is about 3245.6350688271. The cubic root of 10534147 is about 219.2130770232.

Adding to 10534147 its reverse (74143501), we get a palindrome (84677648).

The spelling of 10534147 in words is "ten million, five hundred thirty-four thousand, one hundred forty-seven".

Divisors: 1 13 810319 10534147