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10223113 is a prime number
BaseRepresentation
bin100110111111…
…111000001001
3201020101110211
4212333320021
510104114423
61003041121
7152615665
oct46777011
921211424
1010223113
11585285a
1235101a1
13216c2a4
1415018a5
15d6e10d
hex9bfe09

10223113 has 2 divisors, whose sum is σ = 10223114. Its totient is φ = 10223112.

The previous prime is 10223099. The next prime is 10223123. The reversal of 10223113 is 31132201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10220809 + 2304 = 3197^2 + 48^2 .

It is an emirp because it is prime and its reverse (31132201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10223113 - 29 = 10222601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10223093 and 10223102.

It is not a weakly prime, because it can be changed into another prime (10223123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5111556 + 5111557.

It is an arithmetic number, because the mean of its divisors is an integer number (5111557).

Almost surely, 210223113 is an apocalyptic number.

It is an amenable number.

10223113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10223113 is an equidigital number, since it uses as much as digits as its factorization.

10223113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 10223113 is about 3197.3603175119. The cubic root of 10223113 is about 217.0339728925.

Adding to 10223113 its reverse (31132201), we get a palindrome (41355314).

The spelling of 10223113 in words is "ten million, two hundred twenty-three thousand, one hundred thirteen".