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100531141 = 307327463
BaseRepresentation
bin1011111110111…
…11101111000101
321000011111210121
411333133233011
5201213444031
613550421541
72330333464
oct577375705
9230144717
10100531141
1151824597
12298018b1
1317a9b4a9
14d4cc9db
158c5c011
hex5fdfbc5

100531141 has 4 divisors (see below), whose sum is σ = 100858912. Its totient is φ = 100203372.

The previous prime is 100531127. The next prime is 100531153. The reversal of 100531141 is 141135001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100531141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100531441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163425 + ... + 164038.

It is an arithmetic number, because the mean of its divisors is an integer number (25214728).

Almost surely, 2100531141 is an apocalyptic number.

It is an amenable number.

100531141 is a deficient number, since it is larger than the sum of its proper divisors (327771).

100531141 is an equidigital number, since it uses as much as digits as its factorization.

100531141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 327770.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 100531141 is about 10026.5218794954. The cubic root of 100531141 is about 464.9792120818.

Adding to 100531141 its reverse (141135001), we get a palindrome (241666142).

The spelling of 100531141 in words is "one hundred million, five hundred thirty-one thousand, one hundred forty-one".

Divisors: 1 307 327463 100531141