1005135433 has 2 divisors, whose sum is σ = 1005135434. Its totient is φ = 1005135432.

The previous prime is 1005135401. The next prime is 1005135463. The reversal of 1005135433 is 3345315001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 949379344 + 55756089 = 30812^2 + 7467^2 .

It is a cyclic number.

It is not a de Polignac number, because 1005135433 - 2⁵ = 1005135401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1005135398 and 1005135407.

It is not a weakly prime, because it can be changed into another prime (1005135463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502567716 + 502567717.

It is an arithmetic number, because the mean of its divisors is an integer number (502567717).

Almost surely, 2^1005135433 is an apocalyptic number.

It is an amenable number.

1005135433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1005135433 is an equidigital number, since it uses as much as digits as its factorization.

1005135433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 1005135433 is about 31703.8709466210. The cubic root of 1005135433 is about 1001.7088890348.

The spelling of 1005135433 in words is "one billion, five million, one hundred thirty-five thousand, four hundred thirty-three".