10041113 has 2 divisors, whose sum is σ = 10041114. Its totient is φ = 10041112.

The previous prime is 10041071. The next prime is 10041131. The reversal of 10041113 is 31114001.

10041113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (10041131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6901129 + 3139984 = 2627^2 + 1772^2 .

It is a cyclic number.

It is not a de Polignac number, because 10041113 - 2¹⁸ = 9778969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10041094 and 10041103.

It is not a weakly prime, because it can be changed into another prime (10041173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020556 + 5020557.

It is an arithmetic number, because the mean of its divisors is an integer number (5020557).

Almost surely, 2^10041113 is an apocalyptic number.

It is an amenable number.

10041113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10041113 is an equidigital number, since it uses as much as digits as its factorization.

10041113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 10041113 is about 3168.7715285265. The cubic root of 10041113 is about 215.7383162145.

Adding to 10041113 its reverse (31114001), we get a palindrome (41155114).

The spelling of 10041113 in words is "ten million, forty-one thousand, one hundred thirteen".