1453034353 has 4 divisors (see below), whose sum is σ = 1538506980. Its totient is φ = 1367561728.

The previous prime is 1453034347. The next prime is 1453034369. The reversal of 1453034353 is 3534303541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3534303541 = 73 ⋅48415117.

It can be written as a sum of positive squares in 2 ways, for example, as 638673984 + 814360369 = 25272^2 + 28537^2 .

It is a cyclic number.

It is not a de Polignac number, because 1453034353 - 2⁵ = 1453034321 is a prime.

It is a super-2 number, since 2×1453034353² = 4222617661996257218, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1453034753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42736288 + ... + 42736321.

It is an arithmetic number, because the mean of its divisors is an integer number (384626745).

Almost surely, 2^1453034353 is an apocalyptic number.

It is an amenable number.

1453034353 is a deficient number, since it is larger than the sum of its proper divisors (85472627).

1453034353 is an equidigital number, since it uses as much as digits as its factorization.

1453034353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85472626.

The product of its (nonzero) digits is 32400, while the sum is 31.

The square root of 1453034353 is about 38118.6877135087. The cubic root of 1453034353 is about 1132.6401714007.

Adding to 1453034353 its reverse (3534303541), we get a palindrome (4987337894).

The spelling of 1453034353 in words is "one billion, four hundred fifty-three million, thirty-four thousand, three hundred fifty-three".