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14025433 is a prime number
BaseRepresentation
bin110101100000…
…001011011001
3222101120021111
4311200023121
512042303213
61220340321
7230133322
oct65401331
928346244
1014025433
117a0a574
1248446a1
132ba0b96
141c11449
151370a3d
hexd602d9

14025433 has 2 divisors, whose sum is σ = 14025434. Its totient is φ = 14025432.

The previous prime is 14025419. The next prime is 14025437. The reversal of 14025433 is 33452041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13897984 + 127449 = 3728^2 + 357^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14025433 is a prime.

It is equal to p911614 and since 14025433 and 911614 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (14025437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7012716 + 7012717.

It is an arithmetic number, because the mean of its divisors is an integer number (7012717).

Almost surely, 214025433 is an apocalyptic number.

It is an amenable number.

14025433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14025433 is an equidigital number, since it uses as much as digits as its factorization.

14025433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 22.

The square root of 14025433 is about 3745.0544722340. The cubic root of 14025433 is about 241.1600837206.

Adding to 14025433 its reverse (33452041), we get a palindrome (47477474).

The spelling of 14025433 in words is "fourteen million, twenty-five thousand, four hundred thirty-three".