Base | Representation |
---|---|
bin | 10110101111001100001111… |
… | …111000011010100110000000 |
3 | 111010001220110020111110212100 |
4 | 112233030033320122212000 |
5 | 101101344434420000000 |
6 | 552403210004230400 |
7 | 30030521655142566 |
oct | 2657141770324600 |
9 | 433056406443770 |
10 | 99999990000000 |
11 | 299548373a7012 |
12 | b27080239b400 |
13 | 43a4c6005439c |
14 | 1a9a04d76ba36 |
15 | b86368996a00 |
hex | 5af30fe1a980 |
99999990000000 has 768 divisors, whose sum is σ = 361282278240000. Its totient is φ = 26549376000000.
The previous prime is 99999989999983. The next prime is 99999990000107. The reversal of 99999990000000 is 9999999.
It is a nialpdrome in base 10.
It is a zygodrome in base 10.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 21509997676 + ... + 21510002324.
It is an arithmetic number, because the mean of its divisors is an integer number (470419633125).
Almost surely, 299999990000000 is an apocalyptic number.
99999990000000 is a gapful number since it is divisible by the number (90) formed by its first and last digit.
It is a pronic number, being equal to 9999999×10000000.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 99999990000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (180641139120000).
99999990000000 is an abundant number, since it is smaller than the sum of its proper divisors (261282288240000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
99999990000000 is an frugal number, since it uses more digits than its factorization.
99999990000000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4943 (or 4898 counting only the distinct ones).
The product of its (nonzero) digits is 4782969, while the sum is 63.
Adding to 99999990000000 its reverse (9999999), we get a palindrome (99999999999999).
Subtracting from 99999990000000 its reverse (9999999), we obtain a square (99999980000001 = 99999992).
99999990000000 divided by its reverse (9999999) gives a 7-th power (10000000 = 107).
The spelling of 99999990000000 in words is "ninety-nine trillion, nine hundred ninety-nine billion, nine hundred ninety million", and thus it is an aban number.
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