12111313 has 2 divisors, whose sum is σ = 12111314. Its totient is φ = 12111312.

The previous prime is 12111311. The next prime is 12111331. The reversal of 12111313 is 31311121.

Together with next prime (12111331) it forms an Ormiston pair, because they use the same digits, order apart.

It is a m-pointer prime, because the next prime (12111331) can be obtained adding 12111313 to its product of digits (18).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11716929 + 394384 = 3423^2 + 628^2 .

It is an emirp because it is prime and its reverse (31311121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12111313 - 2¹ = 12111311 is a prime.

Together with 12111311, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 12111293 and 12111302.

It is not a weakly prime, because it can be changed into another prime (12111311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055656 + 6055657.

It is an arithmetic number, because the mean of its divisors is an integer number (6055657).

Almost surely, 2^12111313 is an apocalyptic number.

It is an amenable number.

12111313 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111313 is an equidigital number, since it uses as much as digits as its factorization.

12111313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 18, while the sum is 13.

The square root of 12111313 is about 3480.1311756886. The cubic root of 12111313 is about 229.6485685292.

Adding to 12111313 its reverse (31311121), we get a palindrome (43422434).

The spelling of 12111313 in words is "twelve million, one hundred eleven thousand, three hundred thirteen".