1334996994331 has 112 divisors (see below), whose sum is σ = 1855178584000. Its totient is φ = 960237598320.

The previous prime is 1334996994311. The next prime is 1334996994377.

The cubic root of 1334996994331 is 11011.

It is a perfect power (a cube), and thus also a powerful number.

1334996994331 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 1334996994331 - 2⁵ = 1334996994299 is a prime.

It is a super-2 number, since 2×1334996994331² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1334996994311) by changing a digit.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 102692076481 + ... + 102692076493.

It is an arithmetic number, because the mean of its divisors is an integer number (16564094500).

Almost surely, 2^{1334996994331} is an apocalyptic number.

1334996994331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1334996994331 is a deficient number, since it is larger than the sum of its proper divisors (520181589669).

1334996994331 is an frugal number, since it uses more digits than its factorization.

1334996994331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 126 (or 31 counting only the distinct ones).

The product of its digits is 51018336, while the sum is 64.

Multiplying 1334996994331 by its sum of digits (64), we get a cube (85439807637184 = 44044³).

The spelling of 1334996994331 in words is "one trillion, three hundred thirty-four billion, nine hundred ninety-six million, nine hundred ninety-four thousand, three hundred thirty-one".