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A036058
Summarize digits of preceding number, by decreasing digit value. Start with a(0) = 0.
7
0, 10, 1110, 3110, 132110, 13123110, 23124110, 1413223110, 1423224110, 2413323110, 1433223110, 1433223110, 1433223110, 1433223110, 1433223110, 1433223110, 1433223110, 1433223110, 1433223110, 1433223110, 1433223110
OFFSET
0,2
COMMENTS
This kind of counting sequence is always eventually periodic with period 1, 2 or 3. - Herve Lehning (lehning(AT)noos.fr), Oct 01 2003
LINKS
Herve Lehning, Computer-aided or analytic proof?, College Mathematics Journal, Vol. 21, No. 3, 1990, pp. 228-239.
FORMULA
a(n+1) = A244112(a(n)), a(0) = 0. - M. F. Hasler, Feb 25 2018
EXAMPLE
The third term is 1110 because the second term contains one 1 and one 0.
PROG
(PARI) a(n)=if(n>9, 1433223110, [0, 10, 1110, 3110, 132110, 13123110, 23124110, 1413223110, 1423224110, 2413323110][n+1]) \\ Charles R Greathouse IV, Jul 24 2012
(PARI) a(n, a=0)={for(k=1, n, a==(a=A244112(a))&&break); a} \\ M. F. Hasler, Feb 25 2018
CROSSREFS
Cf. A007890 (same as this, starting at 1), A001155 (same as this, but using method A047842: by increasing digit value), A005150 (as before, starting at 1), A036059 ("fibonacci" based on this), A036066.
Sequence in context: A204577 A210995 A325910 * A001155 A001391 A049064
KEYWORD
nonn,base,easy,nice
STATUS
approved